T9 help! 1

April 25, 2018 2 Comments Uncategorized

Question 1

Die volgende tabel toon die persentasies behaal deur 10 Biometrie studente in ‘n toets (X) en die finale eksamen (Y)./The following table shows the percentages obtained by 10 Biometry students in a test (X) and the final examination (Y).

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind ‘n 99% vertrouensinterval vir die verwagte eksamenpunt indien die toetspunt 70 is. /Find a 99% confidence interval for the expected examination mark if the test mark is 70.

		[68.92 ; 81.91]
		[69.19 ; 81.65]
		[69.97 ; 80.87]
		[63.86 ; 86.98]
		[71.147 ; 79.70]

Question 2

‘n Pearsonkorrelasiekoëffisiënt van 0 (r=0) vir die veranderlikes X en Y impliseer dat:/ A Pearson correlation coefficient of 0 (r=0) for the variables X and Y implies that:
1. daar geen verwantskap tussen X en Y is nie. /there is no relationship between X and Y.

2. X en Y nie gekorreleerd is nie. /X and Y is not correlated

3. daar ‘n gebrek aan lineariteit tussen X en Y is. /there is a lack of linearity between X and Y.

		(i) & (ii)
		(i) & (ii) & (iii)
		(ii) & (iii)
		(ii)
		Geeneen van bogenoemde. / *None of the above*

Question 3

‘n Eenvoudige lineêre regressie analise vir n = 20 data punte het die volgende resultate gelewer: /A simple linear regression analysis for n = 20 data points produced the following results:

?= 2.1 + 3.4x? x = 50 ? y = 212 S_XX = 4.77 S_XY =16.22 S_YY= 59.21

Bepaal SSE. / Find SSE.

		4.0552
		25.148
		42.992
		49.193
		185.094

Question 4

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Toets betekenisvolle regressie. Op ? = 0.01 is die tabel waarde________ . /Test for significance regression. At ? = 0.01 the table value is ________ .

		2.306
		3.169
		2.228
		3.355
		1.397

Question 5

‘n Eenvoudige lineêre regressie analise vir n = 20 data punte het die volgende resultate gelewer: /A simple linear regression analysis for n =20 data points produced the following results:

?= 2.1 + 3.4x? x = 50 ? y = 212 S_XX = 4.77 S_XY =16.22 S_YY= 59.21

Bepaal ‘n 95% vertrouensinterval vir ?as x = 3.0 /Find a 95% confidence interval for ? when x = 3.0.

		[11.9809 ; 12.6191]
		[10.3848 ; 10.8340]
		[10.5763 ; 10.6237]
		[10.1258 ; 11.0742]
		[10.3767 ; 10.8233]

Question 6

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind die vergelyking van die regressielyn wat gebruik kan word om eksamenpunte te beraam vanaf toetspunte./Find the equation of the regression line which can be used to estimate examination marks from test marks.

		? = 29.13 – 0.66x
		? = 0.66 + 29.13x
		? = 0.66 – 29.13x
		? = 29.13 + 0.66x
		? = 79.8 – 81.9x

Question 7

Die volgende tabel toon die persentasies behaal deur 10 Biometrie studente in ‘n toets (X) en die finale eksamen (Y). /The following table shows the percentages obtained by 10 Biometry students in a test (X) and the final examination (Y).

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind ‘n 90% vertrouensinterval vir die verwagte eksamenpunt indien die toetspunt 70 is./Find a 90% confidence interval for the expected examination mark if the test mark is 70.

		[71.97 ; 78.87]
		[69.19 ; 81.65]
		[6901 ; 81.83]
		[71.14 ; 79.70]
		[67.45 ; 83.36]

Question 8

Die volgende tabel toon die persentasies behaal deur 10 Biometrie studente in ‘n toets (X) en die finale eksamen (Y). /The following table shows the percentages obtained by 10 Biometry students in a test (X) and the final examination (Y).

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Toets vir betekenisvolle regressie. Gee die toets statistiek waarde./Test for significance regression. Give the test statistic value.

		2.306
		143.4
		5.04
		5.3363

Question 9

‘n Eenvoudige lineêre regressie analise vir n = 20 data punte het die volgende resultate gelewer: /A simple linear regression analysis for n =20 data points produced the following results:
?= 2.1 + 3.4x? x = 50 ? y = 212 S_XX = 4.77 S_XY =16.22 S_YY= 59.21
Bepaal ‘n 95% vertrouensinterval vir die helling ?. /Find a 95% confidence interval of the slope ?.

		[10.3767 ; 10.8233]
		[2.9434 ; 3.8566]
		[1.1381 ; 5.6619]
		[2.9430 ; 3.8570]
		[3.1907 ; 3.6093]

Question 10

		1.3971
		10.283
		0.2253
		0.2138
		2.7329

Question 11

Die volgende tabel toon die persentasies behaal deur 10 Biometrie studente in ‘n toets (X) en die finale eksamen (Y)./The following table shows the percentages obtained by 10 Biometry students in a test (X) and the final examination (Y).

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind ‘n 95% vertrouensinterval vir die verwagte eksamenpunt indien die toetspunt 70 is./Find a 95% confidence interval for the expected examination mark if the test mark is 70.

		[71.97 ; 78.87]
		[69.19 ; 81.65]
		[69.01 ; 81.83]
		[71.14 ; 79.70]
		[67.45 ; 83.36]

Question 12

Die volgende tabel toon die persentasies behaal deur 10 Biometrie studente in ‘n toets (X) en die finale eksamen (Y)./The following table shows the percentages obtained by 10 Biometry students in a test (X) and the final examination (Y).

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Bereken die korrelasiekoeffisient./Calculate the correlation coefficient.

		0.0011
		0.7606
		0.8721
		0.9989
		0.9980

Question 13

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind die persentasie variasie wat deur die regressie verklaar word. /Find the percentage of variation explained by the regression.

		0.0011 * 100
		0.7606*100
		0.8721*100
		0.9989*100
		0.9980*100

Question 14

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Bereken S_e²./Calculate S_e².

		17.93
		4.23
		143.4
		11.97

Question 15

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Bereken SSE./Calculate SSE.

		17.93
		4.23
		143.4
		11.97

Question 16

X	75	80	93	65	87	71	98	68	84	77
Y	82	78	86	72	91	80	95	72	89	74

Vind ‘n 95% vertouensinterval vir die ? /Find the 95% confidence interval for the ?.

		[0.60 ; 0.71]
		[– 1.2040 ; 2.52]
		[0.62 ; 0.69]
		[– 0.62 ; 1.94]

Question 17

Gegee die inligting van huisgrootte (X) in tien vierkante meters en die verkoopprys (Y) in R 10000 van huise in Bloemfontein: /Given the information on home size (X) in ten squared metres and the sale price (Y) in R 10000 of houses in Bloemfontein:

X	24	32	15	30	26	20	28	32
Y	60	98	36	84	78	50	82	104

Bereken S_XX/Calculate S_XX

970

252.875

3 872

207

Geeneen van bogenoemde. / None of the above

Question 18Gegee die inligting van huisgrootte (X) in tien vierkante meters en die verkoopprys (Y) in R 10000 van huise in Bloemfontein: /Given the information on home size (X) in ten squared metres and the sale price (Y) in R 10000 of houses in Bloemfontein:

X	24	32	15	30	26	20	28	32
Y	60	98	36	84	78	50	82	104

Bereken S_YY/ Calculate S_YY

		970
		525.875
		3 872
		207
		Geeneen van bogenoemde. / *None of the above*

T9 help! 1

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